SSC MTS 6 Aug 2019 Shift 1 Paper

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Question : 42 of 100

Marks: +1, -0

What is the value of

{39÷26+22÷11×2+4×3}/{2\of5-3(7+10÷2-3×3)}

?

$35/2$
$49/2$
$39/2$
$61/2$

Solution:

{39÷26+22÷11×2+4×3}/{2\of5-3(7+10÷2-3×3)}

⇒

{3/2+2×2+4×3}/{10-3(7+5-3×3)}

⇒

{3/2+4+12}/{10-3(12-9)}

⇒

{3/2+16}/{10-9}

⇒ 35/2
∴ The value of the given expression is 35/2.

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