If x and y are two numbers having opposite signs, and x 2 ∶ y 2 = 16 ∶ 81, then what is the value of \frac{3x + 4y}{2x−3y}?

SSC MTS 5 Oct 2021 Shift 1 Paper

Question : 69 of 100

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If x and y are two numbers having opposite signs, and x² ∶ y² = 16 ∶ 81, then what is the value of

\;{3x\;+\;4y}/{2x−3y}?

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