SSC MTS 5 Aug 2019 Shift 3 Paper

Question : 48 of 100

Marks: +1, -0

What is the largest four-digit number, which is divisible by 32, 40, 36 and 48?

Solution:

Tips & Tricks
Factors of 32, 40, 36 and 48
⇒

32 = 2^5

⇒

40 = 2^3 × 5

⇒

36 = 2^2 × 3^2

⇒

48 = 2^4 × 3

⇒ L.C.M. of 32, 40 and 48 =

2^5 × 3^2 × 5

= 1440
⇒ The largest four-digit number = 1440 × 6 = 8640
∴ The largest four-digit number is 8640.

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