SSC MTS 5 Aug 2019 Shift 3 Paper

Follow BODMAS rule to solve this question, as per the order is given below:
Step-1: Parts of an equation enclosed in 'Brackets' must be solved first and in the bracket,
Step-2: Any mathematical 'Of' or 'Exponent' must be solved next,
Step-3: Next, the parts of the equation that contain 'Division' and 'Multiplication' are calculated,
Step-4: Last but not least, the parts of the equation that contain 'Addition' and 'Subtraction' should be calculated.
⇒ $\frac{3\mathrm{of}24÷8\times 3+4÷2-4\times 5}{36÷12\times 4÷2+5\times \left(6-4\right)}$
⇒ $\frac{72÷8\times 3+4÷2-4\times 5}{36÷12\times 4÷2+5\times 2}$
⇒ $\frac{9\times 3+2-4\times 5}{3\times 2+5\times 2}$
⇒ $\frac{27+2-20}{6+10}$
⇒ $\frac{29-20}{16}$
⇒ 9/16