SSC MTS 5 Aug 2019 Shift 3 Paper

Follow BODMAS rule to solve this question, as per the order is given below:
Step-1: Parts of an equation enclosed in ‘Brackets’ must be solved first and in the bracket,
Step-2: Any mathematical ‘Of’ or ‘Exponent’ must be solved next,
Step-3: Next, the parts of the equation that contains ‘Division’ and ‘Multiplication’ are calculated,
Step-4: Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.
Given expression is,
⇒ $\frac{\frac{3}{4}÷\frac{9}{32}+\frac{4}{3}\times \frac{2}{3}\mathrm{of}\frac{27}{16}}{\frac{1}{2}\times \left(\frac{8}{3}-2\right)÷\frac{4}{9}\left(\frac{1}{3}+\frac{1}{6}\right)}$
⇒ $\frac{\frac{3}{4}÷\frac{9}{32}+\frac{4}{3}\times \frac{2}{3}\mathrm{of}\frac{27}{16}}{\frac{1}{2}\times \left(\frac{2}{3}\right)÷\frac{4}{9}+\left(\frac{1}{2}\right)}$
⇒ $\frac{\frac{3}{4}÷\frac{9}{32}+\frac{4}{3}\times \frac{9}{8}}{\frac{1}{2}\times \left(\frac{2}{3}\right)÷\frac{4}{9}+\left(\frac{1}{2}\right)}$
⇒ $\frac{\frac{8}{3}+\frac{4}{3}\times \frac{9}{8}}{\frac{1}{2}\times \left(\frac{3}{2}\right)+\left(\frac{1}{2}\right)}$
⇒ $\frac{\frac{8}{3}+\frac{3}{2}}{\frac{3}{4}+\left(\frac{1}{2}\right)}$
⇒ $\frac{\frac{25}{6}}{\frac{5}{4}}$
⇒ 10/3