SSC MTS 5 Aug 2019 Shift 2 Paper

Speed = distance/time
⇒ Speed of train = {(length of platform + length of train)/time taken by train to cross platform}
= (900 + 600)/300 = 5 m/sec.
⇒ Time = distance /speed = length of train / Speed of train = 600/5
⇒ Time = 120 seconds
⇒ Time = 120/60 = 2 minutes
∴ Train crosses a stationary pole in 2 minutes.