SSC MTS 5 Aug 2019 Shift 2 Paper

3 – 1 = 2, 4 – 2 = 2, 5 – 3 = 2
⇒ L.C.M. of 3, 4 and 5 is 60
⇒ Required 3 digit number = 60 × 2 = 120
⇒ 3 digit number when divided by 3, 4 and 5 leaves remainders 1, 2 and 3 respectively
= 120 – 2 = 118
⇒ The sum of the digits of 118 = 1 + 1 + 8 = 10
∴ The sum of the digits is 10.