SSC MTS 5 Aug 2019 Shift 2 Paper

The radius of sphere = r
The radius of the base of right circular cylinder = R
Height of right circular cylinder = h
r = R = h (Given)
⇒ Surface area of sphere = 4 × $\mathrm{\pi }\times {\mathrm{r}}^2=4\mathrm{\pi }{\mathrm{r}}^2$
⇒ Curved surface area of cylinder = 2 × $\mathrm{\pi }$ × R × h = 2 × $\mathrm{\pi }$ × r × r = $2\mathrm{\pi }{\mathrm{r}}^2$
⇒ The surface area of the sphere : Curved surface area of cylinder = $4\mathrm{\pi }{\mathrm{r}}^2:2\mathrm{\pi }{\mathrm{r}}^2$
⇒ The surface area of the sphere : Curved surface area of cylinder = 2 : 1
∴ The ratio of the surface area of sphere and curved surface area of the cylinder is 2 : 1.