SSC MTS 2 Aug 2019 Shift 3 Paper

Follow BODMAS rule to solve this question, as per the order is given below:
Step-1: Parts of an equation enclosed in ‘Brackets’ must be solved first and in the bracket,
Step-2: Any mathematical ‘Of’ or ‘Exponent’ must be solved next,
Step-3: Next, the parts of the equation that contains ‘Division’ and ‘Multiplication’ are calculated,
Step-4: Last but not least, the parts of the equation that contain ‘Addition’ and ‘Subtraction’ should be calculated.
Given expression is,
$\frac{3}{7}÷\frac{9}{21}+2-\frac{4}{3}+\frac{1}{2}\mathrm{o}\mathrm{f}\frac{12}{5}\times \frac{25}{18}÷\frac{5}{9}$
$\Rightarrow \frac{3}{7}÷\frac{9}{21}+2-\frac{4}{3}+\frac{6}{5}\times \frac{25}{18}÷\frac{5}{9}$
$\Rightarrow \frac{3}{7}÷\frac{9}{21}+2-\frac{4}{3}+\frac{6}{5}\times \frac{25}{18}\times \frac{9}{5}$
⇒ $1+2-\frac{4}{3}+3$
$\Rightarrow 6-\frac{4}{3}$
$\Rightarrow \frac{14}{3}$
∴ Required answer is 14/3.