SSC MTS 2 Aug 2019 Shift 1 Paper

Calculation:
Let total work be 60x units (LCM of 10, 15, 60)
⇒ Efficiency of A = 6x units/day
⇒ Efficiency of B = 4x units/day
⇒ Efficiency of C = x units/day
⇒ Work done in 5 days by A & B = (6x + 4x) × 5 = 50x units
⇒ Remaining work = 60x – 50x = 10x units
This work is completed by B & C
⇒ Time taken to complete the remaining work = 10x/ (4x + x)
= 10x/5x = 2 days
⇒ Total time taken to complete the work = 5 + 2 = 7 days