SSC JE Mechanical Engineering 27 Sep 2019 Shift 2 Paper

Question : 154 of 200

Marks: +1, -0

What will be the specific enthalpy of steam at pressure of 2 MPa and dryness fraction of 0.9?
[Where, properties of steam at 2 MPa are: specific enthalpy of saturated liquid = 900 kJ/kg, specific enthalpy of saturated vapour = 2800 kJ/kg.]

2610 kJ/kg
2500 kJ/kg
2680 kJ/kg
2570 kJ/kg

Validate

Solution:

Given:

{h}_{{f}}=900 {kJ} \/ {kg} ; {h}_{{g}}=2800 {kJ} \/ {kg} ; {x}=0.9

Substituting the given values in the equation 1

h = 900 + 0.9 × (2800 - 900)

∴ h = 2610

kJ/kg

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