SSC JE Mechanical Engineering 27 Sep 2019 Shift 1 Paper

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Question : 187 of 200

Marks: +1, -0

The specific gravity of a liquid is 2.5. Assuming g = 9.8

m\/s^2

, the mass of 1 litre of the liquid is:

24.5 kg
2.5 kg
1.0 kg
9.8 kg

Solution:

Given:
S.G.

=2.5

and volume

{V}=1

lit.
Density

\ ρ=2.5 \×1000=2500 {kg} \/ {m}^{3}

and volume

{V}=1 \×10^{-3}=0.001 {m}^{3}

Mass

{M}=2500 \×0.001=2.5 {kg}

.

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