SSC JE Mechanical Engineering 27 Sep 2019 Shift 1 Paper

Question : 152 of 200

Marks: +1, -0

The flow rate is

1 {m}^{3} \/ {s}

in a pipe of radius

1 {m}

. The velocity of the fluid is approximately:

Solution:

Given:

Q=1 {m}^{3} \/ {s}

and radius

r=1 {m}

Q=A V=\πr^{2} \×V=\π(1)^{2} \×V=\πV \

1=\πV \⇒V=1 \/ \π\ {m} \/ {s}

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