SSC JE Mechanical Engineering 27 Sep 2019 Shift 1 Paper

Question : 125 of 200

Marks: +1, -0

Fluid flows through a converging nozzle, with the exit diameter equal to half the entrance diameter. Assuming an ideal flow, if the velocity at the entrance is 2 m/s, then the velocity at the exit is:

16 m/s
32 m/s
8 m/s
4 m/s

Validate

Solution:

Given:

{d}_{2}={d}_{1} \/ 2, {V}_{1}=2 {m} \/ {s}

{A}_{1} {V}_{1}={A}_{2} {V}_{2}

{{V}_{2}}/{{V}_{1}}={{A}_{1}}/{{A}_{2}}=({{d}_{1}}/{{d}_{2}})^{2}=2^{2}=4 \

⇒ {V}_{2}=4 {V}_{1}=8 {m} \/ {s}

Go to Question:

Prev Question

Next Question