SSC JE Mechanical Engineering 27 Oct 2020 Shift 2 Papers

Question : 169 of 200

Marks: +1, -0

If Poisson’s ratio of an elastic material is 0.4, then what will be the ratio of modulus of rigidity of Young’s modulus?

Solution:

μ = 0.4

E = 2G (1 + μ)

G/E=1/{2(1+μ)}=1/{2(1+0.4)}

=0.357

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