SSC JE Mechanical Engineering 27 Oct 2020 Shift 2 Papers

Diameter of plunger, d = 3 cm, Diameter of ram, D = 20 cm, Force required at the plunger = ?, Weight = 30 kN
According to pascals law,
Pressure applied at ram = Pressure exerted on the plunger
$\frac{{\mathit{F}}_1}{{\mathit{A}}_1}=\frac{{\mathit{F}}_2}{{\mathit{A}}_2}$
$\frac{30000}{\frac{\mathit{\pi }{\mathit{D}}^2}{4}}=\frac{{\mathit{F}}_2}{\frac{\mathit{\pi }{\mathit{d}}^2}{4}}$
$\therefore {\mathit{F}}_2=\frac{{\mathit{d}}^2}{{\mathit{D}}^2}\times 30000$ $=\frac{3^2}{{20}^2}\times 30000=675\mathit{k}\mathit{N}$
Here, ${\mathit{F}}_2=$ force required on the plunger