SSC JE Mechanical Engineering 27 Oct 2020 Shift 2 Papers

Question : 128 of 200

Marks: +1, -0

A heat engine is supplied with 450 kJ/s of heat at a constant fixed temperature of 227°C. The heat is rejected at 27°C. What will be the amount of heat rejected if the cycle is reversible?

300 kW
270 kW
330 kW
320 kW

Validate

Solution:

Q_S = 450 kJ/s, T_R = 27°C = 300 K,

T_S = 227°C = 500 K

η=1−T_R/T_S=1−300/500=0.4

η=W/Q_S=1−Q_R/Q_S

Q_R=270

kW
∴ Q = 270 kW or 270 kJ/s

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