SSC JE Mechanical Engineering 27 Oct 2020 Shift 2 Papers

Question : 102 of 200

Marks: +1, -0

A Newtonian fluid fills the clearance between a shaft and a sleeve. When a force of 0.9 kN is applied to the shaft parallel to the sleeve, the shaft attains a speed of 1.25 cm/s. What will be the speed of the shaft if a force of 3 kN is applied?

4.16 cm/s
5.19 cm/s
5.26 cm/s
6.32 cm/s

Validate

Solution:

Given:

{F}_{2}=3 {kN}, {F}_{1}=0.9 {kN}, {u}_{1}=1.25 {cm} \/ {s}

∴ F_2/F_1=u_2/u_1

\∴{3}/{0.9}={{u}_{2}}/{1.25}

∴ u_2 = 4.166

cm/s

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