SSC JE Mechanical Engineering 27 Oct 2020 Shift 1 Papers

According to the given information:
B is twice as heavy as A
B = 2 × A
C is 20 kg heavier than E
C = 20 + E
D is one and a half times as heavy as E
D = 1.5 × E
C is four times as heavy as A
C = 4 × A
A = C ÷ 4
Weight of E is 20 kg
E = 20 kg
C = 20 + 20 = 40 kg
D = 1.5 × 20 = 30 kg
A = 40 ÷ 4 = 10 kg
B = 2 × 10 = 20 kg
So, the ascending order of the weight of the objects is:
A < B = E < D < C
Hence, the heaviest object is "C, 40 kg".