SSC JE Mechanical Engineering 27 Oct 2020 Shift 1 Papers

Question : 136 of 200

Marks: +1, -0

How many chlorine atoms does the refrigerant R – 134a contain?

Eight
Seven
One
Nil

Solution:

Given:
For R - 134a, we have m – 1 = 1 i.e. m = 2
n + 1 = 3 i.e. n = 2 and p = 4
It must satisfy this 2m + 2 = n + p + q therefore, we get q = 0
Therefore, we get,

C_2H_2F_4

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