SSC JE Mechanical Engineering 25 Sep 2019 Shift 1 Paper

Question : 181 of 200

Marks: +1, -0

The head loss due to the friction in a pipe of length 9.81 m, diameter 1 m, the velocity of water = 2 m/s and friction factor = 0.06 is:

Solution:

Given:
f’ = 4f = 0.06 (f is friction coefficient), L = 9.81 m, V = 2 m/s, g = 9.81 m/s

^{2}

, d = 1 m

h_f={f′LV^2}/{2gd}={0.06 × 9.81 × 4}/{2 × 9.81 × 1}

h _f = 0.12 m

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