SSC JE Mechanical Engineering 25 Sep 2019 Shift 1 Paper

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Question : 149 of 200

Marks: +1, -0

\Ψ = 3x^2 -y^3

represents a stream function in a two – dimensional flow. The velocity component in ‘x’ direction at the point (1, 3) is:

– 24 m/s
4 m/s
27 m/s
31.5 m/s

Solution:

Given:

\Ψ = 3x^2 -y^3

u=-\ 𝜕 \Ψ \/ \ 𝜕 y=-(-3 y^{2})

u=3 y^{2}

u at

(1,3)

{u}=3 {y}^{2}=3 \×(3)^{2}=27 {m} \/ {s}

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