SSC JE Mechanical Engineering 25 Sep 2019 Shift 1 Paper

Question : 130 of 200

Marks: +1, -0

The Brake-specific fuel consumption (BSFC) of a diesel engine is 200 gm/kWh. If the calorific value of diesel is 40 MJ/kg, the brake thermal efficiency is

28.4%
31%
45%
39.5%

Validate

Solution:

CV = 40 MJ/kg = 40 × 10

^{6}

J/kg.
BSFC=200 gm/kWh

={200 \×10^{-3}}/{(3600 \×10^{3})} {kg} \/ {J}={1}/{18} \×10^{-6} {kg} \/ {J}

\η={1}/{({1}/{18}) \×10^{-6} \×40 \×10^{6}}

={18}/{40}=0.45=45 \%

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