SSC JE Mechanical Engineering 25 Sep 2019 Shift 1 Paper

Question : 124 of 200

Marks: +1, -0

A pipe of diameter 10 cm, carrying water at 5 m/s, reduces into a smaller diameter of 5 cm. The velocity in the smallest diameter section is:

Solution:

Given:

{D}_{1}=10 {cm}, {D}_{2}=5 {cm}, {V}_{1}=5 {m} \/ {s}

{A}_{1} \×{V}_{1}={A}_{2} \×{V}_{2}

{D}_{1}/{ }^{2} \×{V}_{1}={D}_{2}{ }^{2} \×{V}_{2}

(10)^{2} \×5=(5)^{2} \×V_{2}

{V}_{2}=20 {m} \/ {s}

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