SSC JE Mechanical Engineering 25 Sep 2019 Shift 1 Paper

Question : 117 of 200

Marks: +1, -0

A piston of 0.1 m diameter expands over a stroke of 0.2 m under constant gas pressure of 2 × 105 N/m

^{2}

. The work done by the piston is:

Solution:

Given:

{P}=2 \×10^{5} {N} \/ {m}^{2}

{d}=0.1 {m}, {L}=0.2 {m}

{V}={\π}/{4} \×0.1^{2} \×0.2

{V}={3.14159}/{4} \×0.1^{2} \×0.2

=0.001571 {m}^{3}

{W}={P} \×{V}

{W}=2 \×10^{5} \×0.001571

=314.2 {J}

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