There are 11 players in the tournament and each player has to play with every other once. 1 player will play 10 games → 10 2 player will have 9 games as his game with player 1 is already counted → 9 3 player will have 8 unique games as 2 of his games are already counted → 8 Similarly, 4 → 7 5 → 6 7 → 5 8 → 4 9 → 3 10 → 2 11 → 1 Total number of games = 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 55 Hence, “55” is the correct answer.