SSC JE Mechanical Engineering 22 Mar 2021 Shift 2 Papers

Question : 138 of 199

Marks: +1, -0

A member of length 200 mm and diameter 25 mm is subjected to a tensile load of 20 kN. The final length of the member is found to be 220 mm. The percentage increase in the length of the member is

Validate

Solution:

L_f = 220

mm,

L_i = 200

mm
Then,
Percentage change in the length

= {L_f−L_i}/L_i×100

= {220−200}/200×100

= 10%

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