SSC JE Mechanical Engineering 22 Mar 2021 Shift 1 Papers

Question : 115 of 200

Marks: +1, -0

Determine the COP (coefficient of performance) of a heat pump if the rate of heat rejected is 360 kJ/min and power supplied is 2 kW.

Solution:

Rate of heat rejected,

Q_1 = 360

kJ/min = 36060 kJ/sec = 6 kW, power supplied, W = 2 kW
coefficient of performance of a heat pump

COP = Q_1/W

= 6/2

= 3

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