SSC JE Mechanical Engineering 22 Mar 2021 Shift 1 Papers

Question : 105 of 200

Marks: +1, -0

An oil of specific gravity 0.7 is stored in a closed tank up to a height of 2 m. What will be the gauge pressure at the bottom of the tank?

Solution:

Specific gravity

= {\Density\of\fluid}/{\Density\of\water }= 0.7

g = 10 m

^2

/s
h = 2m
ρ = 0.7 × 1000 = 700 Kg/m

^3

P = ρgh = 700 × 10 × 2 = 14000 Pa
P = 0.014 MPa

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