SSC JE Mechanical Engineering 2018 Set 3 Paper

Question : 34 of 200

Marks: +1, -0

If 21 # 11 = 5, 18 # 4 = 7 and 6 # 2 = 2, then find the value of 13 # 5 = ?

Solution:

21#11 = 5 ↔

[{21-11}/2=5]

18#4 = 7 ↔

[{18-4}/2=7]

6#2 = 2 ↔

[{6-2}/2=4]

13#5 = 4 ↔

[{13-5}/2=4]

Answer

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