SSC JE Mechanical Engineering 2018 Set 3 Paper

Question : 106 of 200

Marks: +1, -0

What is the velocity ratio for a slip in the belt drive system?

Solution:

Velocity ratio

N_2/N_1={d_1+t}/{d_2+t}(1-S/100)

where N

_1

and N

_2

speed of pulley

d_1

and

d_2

diameter of pulley
't' is thickness of belt
's' is sleep of belt.

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