SSC JE Mechanical Engineering 2018 Set 2 Paper

Question : 179 of 200

Marks: +1, -0

Time of flow from one tank in which water level is

h_1

to another tank having

h_2

will be proportional to
A.

h_1 -h_2

√{h_1 -h_2}

√h_1 -√h_2

{h_1^{3\/2}} -{h_2^{3\/2}}

Solution:

Time of flow by orifice

T={2A[√H_1-√H_2]}/{Cd.d√{2g}}

Time of flow by triangular notch

T={{5A}/{4Cd.\tanθ/2√{2g}}[{1/{H_2^{3\/2}-H_1^{3\/2}}]

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