SSC JE Mechanical Engineering 2018 Set 2 Paper

Question : 134 of 200

Marks: +1, -0

While working between temperatures 150 K and 300 K, the entropy change experienced by the Carnot engine during heat addition is 1 kJ/K, the work produced (kJ) by the engine is ________.

Validate

Solution:

∵ ds={dQ}/T

1 KJ / k

={DQ}/300⇒Q_1=300

KJ / kg
from carnot cycle

Q_2 = 150

kJ/kg

Q_1/T_1=Q_2/T_2

Workdone

w = Q_1 -Q_2 = 300 -150 = 150

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