SSC JE Mechanical Engineering 2018 Set 2 Paper

Question : 130 of 200

Marks: +1, -0

Which is the CORRECT option for the polar moment of inertia of the solid shaft?

Solution:

Poler moment of inertia for solid shaft

J =π/32d ^2

Polar moment of inertia for Hollow shaft

J =π/32(D^2-d ^4)

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