SSC JE Mechanical Engineering 2018 Set 2 Paper

Question : 125 of 200

Marks: +1, -0

What is the volumetric strain in the thin cylinder subjected to internal pressure having hoop stress of 200 MPa, modulus of elasticity, E=200 GPa and poissons ratio=0.25?

$20/1000$
$2/1000$
$0.2/1000$
$0.02/1000$

Validate

Solution:

Given hoop stress

(σ_C) = 200

mPa

E = 200 GPa = 200 × 10^3

mPa
Poisson ratio µ = 0.25
Volumetric strain for thin cylinder

{∆V/V={pd}/{P4tE} [5-4µ]

=200/{2×200×10^3}[5-4×0.25]

=2/1000

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