SSC JE Mechanical Engineering 2018 Set 2 Paper

Question : 120 of 200

Marks: +1, -0

The equivalent length of the column when both the ends are fixed is ________.

Solution:

Euler's load for different column with different condition

End Condition	Effective lengh
1. Both end hinged	$L_e = L$
2. One end fixed other free	$L_e = 2L$
3. Both end fixed	$L_e= L/2$
4. One end fixed and other hinged	$L_e= L/√2$

Go to Question:

Prev Question

Next Question