SSC JE Mechanical Engineering 2018 Set 2 Paper

In the given figure number of link = 5
Number of pair = 5
Degree of freedom from Kulzback equation
$\mathit{F}=3\left(\mathit{l}-1\right)-2\mathit{J}-\mathit{h}$
$=3\left(5-1\right)-2\times 5-0=2$
Pair between link
link 5 and 1 → P${}_1$
link 1 and 2 → P${}_2$
link 2 and 3 → P${}_3$
link 3 and 4 → P${}_4$
link 4 and 5 → P${}_5$
where P is the pair.