SSC JE Mechanical Engineering 2018 Set 1 Paper

Question : 114 of 200

Marks: +1, -0

Which ratio defines the height of a watt governor to that of the porter governor for equal arm and link lengths, where m is the mass of the ball and M is the mass of the sleeve?

$m/{M+m}$
$M/{M+m}$
${M+m}/m$
${M+m}/M$

Validate

Solution:

Height of watt governor

h = 895/ N^2

Height of porter governor

h = {M+m}/m × 895/ N^2

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