SSC JE Mechanical Engineering 2017 Set 5 Paper

Question : 187 of 200

Marks: +1, -0

A load of 20,000 kg applied to a brass cylinder 40 cm long and 10 cm in diameter caused the length to increase 0.8 cm and the diameter to decrease 0.005 cm. Poisson’s ratio of brass is _____.

0.025
0.925
0.25
2.5

Validate

Solution:

Poisson’s ratio is given as

υ = \text" - Lateral strain"/\text"longitudinal strain"

={0.005/10}/{0.8/40}=0.02/80

= 0.025

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