SSC JE Mechanical Engineering 2017 Set 5 Paper

Question : 136 of 200

Marks: +1, -0

Two small orifices A and B of diameters 1 cm and 2 cm, respectively, are placed on the sides of a tank at depths of

h_1

and

h_2

below the open liquid surface. If the discharges through A and B are equal, then the ratio of

h_1

and

h_2

(assuming Cd values) will be __.

Solution:

Discharge through orifice A is given by

Q_A=A_AV_A

=(π/4)1^2×√{2gh_1}

Discharge through orifice B is given by

Q_B=A_BV_B

=(π/4)2^2×√{2gh_2}

Equating the two discharge, we get

Q_A=Q_B

1×√h_1=4×√h_2

∴h_1:h_2=16:1

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