SSC JE Mechanical Engineering 2017 Set 5 Paper

Question : 128 of 200

Marks: +1, -0

A refrigeration cycle operates between condenser temperature of + 27°C and evaporator temperature of –23°C. The Carnot coefficient of performance of cycle will be _____.

Validate

Solution:

Carnot COP of refrigeration cycle is given as

\COP=T_L/{T_H-T_L}

={273-23}/{27-(-23)}

\COP=250/50=5

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