SSC JE Mechanical Engineering 2017 Set 4 Paper

Weight (mass) of a particle = 3 kg (Air) = 2.5 kg (water)
* Weight difference = 0.5 kg = (Buoyant force of water)
${\mathit{F}}_{\mathit{b}}$ (Buoyant force) = ${\left(\mathit{\rho }\right)}_{\mathrm{water}}$ × g × volume of a body $\left({\mathit{V}}_{\mathit{b}}\right)$
0.5 = ρ × 9.81 × ${\mathit{V}}_{\mathit{b}}$
${\mathit{V}}_{\mathit{b}}=\frac{0.5}{1000\times 9.81}$
specitic gravity
* density of Body (ρ) $=\frac{{\mathit{m}}_{\mathit{b}}}{{\mathit{v}}_{\mathit{b}}}=\frac{3}{\left(\frac{0.5}{1000\times 9.81}\right)}$ = 6000
sp. gravity $=\frac{6000}{1000}=6$