SSC JE Mechanical Engineering 2017 Set 2 Paper

Question : 33 of 200

Marks: +1, -0

In a certain code language, ‘+’ represents ‘×’, ‘–’ represents ‘+’, ‘×’ represents ‘÷’ and ‘÷’ represents ‘–’. Find out the answer to the following question 0.02 + 400 – 123 × 3 = ?

–33
49
0.2
36

Validate

Solution:

(+) ⇒ (×), (–) ⇒ (+), (×) ⇒ (÷), (÷) ⇒ (–)
Change the sign of given equation, with the condition we get,
(0.02 × 400) + (123 ÷ 3)
= (0.02 × 400) +

123/3

= 8 + 41 = 49

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