SSC JE Mechanical Engineering 2017 Set 2 Paper

Question : 196 of 200

Marks: +1, -0

Efficiency of the Carnot engine is given as 80%. If the cycle direction be reversed. what will be the value of coefficient of performance of reversed Carnot cycle?

1.25
0.8
0.5
0.25

Validate

Solution:

\COP_{\HP}=1/n_{\carnot}=1/0.80

\COP_\R = \COP_\HP - 1

\COP_\R=1/0.80-1=0.25

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