SSC JE Mechanical Engineering 2017 Set 2 Paper

Question : 105 of 200

Marks: +1, -0

A body is vibrating at 10 vibrations/second in Simple Harmonic Motion of 10 cm amplitude. The maximum velocity in cm/sec can be _____.

Solution:

For velocity to be maximum in SHM

\V_\max

= 2πfA
Where, ‘f’ is frequency and a is maximum amplitude.

\VV_\max

= 2π × 10 × 10 = 200π.

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