SSC JE Mechanical Engineering 2015 Paper

Question : 137 of 200

Marks: +1, -0

A body of mass 5 kg accelerates at a constant rate of 2 m/s

^{2}

on a smooth horizontal surface due to an external force acting at 30° with horizontal.
The magnitude of the force is

Solution:

F cos30° = ma

F={5×2}/ {\cos30°}

[F={10}/ {\cos30°}N]

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