SSC JE Mechanical Engineering 2014 Set 2 Paper

Question : 134 of 200

Marks: +1, -0

A body of mass 5 kg is pushed up to 2 m on a smoth 30° incline by a force of 60 N acting parallel to the plane. The work done- on the body is :

Solution:

Given m = 5 kg
θ = 30°
d = 3m
F = 60 N

from

\sin 30°=x/2

⇒

x= 2 \sin30°

Energy conservation workdone = mgh

5 × 9.81 × 2 \sin 30° = 49.05\J

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