SSC JE Mechanical Engineering 2014 Set 1 Paper

Question : 132 of 200

Marks: +1, -0

The boiling and freezing points for water aremarked on a temperature scale P as 130°P and–20°P respectively. What will be the reading onthis scale corresponding to 60C on Celsius scale ?

60°P
70°P
90°P
110°P

Validate

Solution:

Equating gradient of both the scales between freezing and steam or boiling point,

[(BP -\Unknown ) / (BP -FP) ]_{\Scale-1}

= [(BP -\Unknown ) / (BP -FP) ]_{\Scale-2}

[{ \{130 -(P) \} / {\{130 -(-20)\}} ] = [ (100 -60)/(100 -0) ]

→ P = 130 -[ {40/100} × 150 ]

= 70°P

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