SSC JE Mechanical Engineering 2014 Set 1 Paper

Question : 128 of 200

Marks: +1, -0

The angle turned by a wheel while it starts from rest and accelerates at constant rate of 3 rad/s

^{2}

for an interval of 20 sec is

Solution:

Using equation of motion for circular path as  = 0 + ½  t 2 ;

θ= ω_0 + 1/2 α\ t^2;

θ=0+1/2×3 ×20^2 = 600

rad /s

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