SSC JE Mechanical Engineering 2014 Set 1 Paper

Question : 102 of 200

Marks: +1, -0

The shearing strength of a rivet is 50 N/mm

^{2}

. If the diameter of the rivet is doubled, then its shearing strength will be

Solution:

Shearing strength of rivet

P_s = n ×{πd^2}/4 ×τ_s

Given

P_s = 50 \N\/\m^2

d_\new = 2d

Then

P_s = n ×π/4({ 2d} )^2 ×τ_s

4 × 50 = 200

N/m

^{2}

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